Solve 105/8div421/2

$$10 \frac{ 5 }{ 8 } \div 42 \frac{ 1 }{ 2 }$$

Evaluate

$$\frac{1}{4}=0.25$$

Solution Steps

Divide \frac{10\times 8+5}{8} by \frac{42\times 2+1}{2} by multiplying \frac{10\times 8+5}{8} by the reciprocal of \frac{42\times 2+1}{2}.

$$\frac{\left(10\times 8+5\right)\times 2}{8\left(42\times 2+1\right)}$$

Cancel out 2 in both numerator and denominator.

$$\frac{5+8\times 10}{4\left(1+2\times 42\right)}$$

Multiply 8 and 10 to get 80.

$$\frac{5+80}{4\left(1+2\times 42\right)}$$

Add 5 and 80 to get 85.

$$\frac{85}{4\left(1+2\times 42\right)}$$

Multiply 2 and 42 to get 84.

$$\frac{85}{4\left(1+84\right)}$$

Add 1 and 84 to get 85.

$$\frac{85}{4\times 85}$$

Multiply 4 and 85 to get 340.

$$\frac{85}{340}$$

Reduce the fraction \frac{85}{340} to lowest terms by extracting and canceling out 85.

$$\frac{1}{4}$$

Factor

$$\frac{1}{2 ^ {2}} = 0.25$$