Solve 107/12-1/3=

$$10 \frac { 7 } { 12 } - \frac { 1 } { 3 } =$$

Evaluate

$$\frac{41}{4}=10.25$$

Solution Steps

Multiply 10 and 12 to get 120.

$$\frac{120+7}{12}-\frac{1}{3}$$

Add 120 and 7 to get 127.

$$\frac{127}{12}-\frac{1}{3}$$

Least common multiple of 12 and 3 is 12. Convert \frac{127}{12} and \frac{1}{3} to fractions with denominator 12.

$$\frac{127}{12}-\frac{4}{12}$$

Since \frac{127}{12} and \frac{4}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{127-4}{12}$$

Subtract 4 from 127 to get 123.

$$\frac{123}{12}$$

Reduce the fraction \frac{123}{12} to lowest terms by extracting and canceling out 3.

$$\frac{41}{4}$$

Factor

$$\frac{41}{2 ^ {2}} = 10\frac{1}{4} = 10.25$$