Solve 103/4-11/5*61/4

$$10 \frac { 3 } { 4 } - 1 \frac { 1 } { 5 } \cdot 6 \frac { 1 } { 4 }$$

Evaluate

$$\frac{13}{4}=3.25$$

Solution Steps

Multiply 10 and 4 to get 40.

$$\frac{40+3}{4}-\frac{1\times 5+1}{5}\times \frac{6\times 4+1}{4}$$

Add 40 and 3 to get 43.

$$\frac{43}{4}-\frac{1\times 5+1}{5}\times \frac{6\times 4+1}{4}$$

Multiply 1 and 5 to get 5.

$$\frac{43}{4}-\frac{5+1}{5}\times \frac{6\times 4+1}{4}$$

Add 5 and 1 to get 6.

$$\frac{43}{4}-\frac{6}{5}\times \frac{6\times 4+1}{4}$$

Multiply 6 and 4 to get 24.

$$\frac{43}{4}-\frac{6}{5}\times \frac{24+1}{4}$$

Add 24 and 1 to get 25.

$$\frac{43}{4}-\frac{6}{5}\times \frac{25}{4}$$

Multiply \frac{6}{5} times \frac{25}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{43}{4}-\frac{6\times 25}{5\times 4}$$

Do the multiplications in the fraction \frac{6\times 25}{5\times 4}.

$$\frac{43}{4}-\frac{150}{20}$$

Reduce the fraction \frac{150}{20} to lowest terms by extracting and canceling out 10.

$$\frac{43}{4}-\frac{15}{2}$$

Least common multiple of 4 and 2 is 4. Convert \frac{43}{4} and \frac{15}{2} to fractions with denominator 4.

$$\frac{43}{4}-\frac{30}{4}$$

Since \frac{43}{4} and \frac{30}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{43-30}{4}$$

Subtract 30 from 43 to get 13.

$$\frac{13}{4}$$

Factor

$$\frac{13}{2 ^ {2}} = 3\frac{1}{4} = 3.25$$