Solve 101/2-[81/2+{7-6-4}]

$$10 \frac { 1 } { 2 } - [ 8 \frac { 1 } { 2 } + \{ 7 - 6 - 4 \} ]$$

Evaluate

$$5$$

Solution Steps

Multiply 10 and 2 to get 20.

$$\frac{20+1}{2}-\left(\frac{8\times 2+1}{2}+7-6-4\right)$$

Add 20 and 1 to get 21.

$$\frac{21}{2}-\left(\frac{8\times 2+1}{2}+7-6-4\right)$$

Multiply 8 and 2 to get 16.

$$\frac{21}{2}-\left(\frac{16+1}{2}+7-6-4\right)$$

Add 16 and 1 to get 17.

$$\frac{21}{2}-\left(\frac{17}{2}+7-6-4\right)$$

Convert 7 to fraction \frac{14}{2}.

$$\frac{21}{2}-\left(\frac{17}{2}+\frac{14}{2}-6-4\right)$$

Since \frac{17}{2} and \frac{14}{2} have the same denominator, add them by adding their numerators.

$$\frac{21}{2}-\left(\frac{17+14}{2}-6-4\right)$$

Add 17 and 14 to get 31.

$$\frac{21}{2}-\left(\frac{31}{2}-6-4\right)$$

Convert 6 to fraction \frac{12}{2}.

$$\frac{21}{2}-\left(\frac{31}{2}-\frac{12}{2}-4\right)$$

Since \frac{31}{2} and \frac{12}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{21}{2}-\left(\frac{31-12}{2}-4\right)$$

Subtract 12 from 31 to get 19.

$$\frac{21}{2}-\left(\frac{19}{2}-4\right)$$

Convert 4 to fraction \frac{8}{2}.

$$\frac{21}{2}-\left(\frac{19}{2}-\frac{8}{2}\right)$$

Since \frac{19}{2} and \frac{8}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{21}{2}-\frac{19-8}{2}$$

Subtract 8 from 19 to get 11.

$$\frac{21}{2}-\frac{11}{2}$$

Since \frac{21}{2} and \frac{11}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{21-11}{2}$$

Subtract 11 from 21 to get 10.

$$\frac{10}{2}$$

Divide 10 by 2 to get 5.

$$5$$

Factor

$$5$$