Solve 10*(7/5)^2-69*(7/5)+92

$$10 \cdot ( \frac { 7 } { 5 } ) ^ { 2 } - 69 \cdot ( \frac { 7 } { 5 } ) + 92$$

Evaluate

$$15$$

Solution Steps

Calculate \frac{7}{5} to the power of 2 and get \frac{49}{25}.

$$10\times \frac{49}{25}-69\times \frac{7}{5}+92$$

Express 10\times \frac{49}{25} as a single fraction.

$$\frac{10\times 49}{25}-69\times \frac{7}{5}+92$$

Multiply 10 and 49 to get 490.

$$\frac{490}{25}-69\times \frac{7}{5}+92$$

Reduce the fraction \frac{490}{25} to lowest terms by extracting and canceling out 5.

$$\frac{98}{5}-69\times \frac{7}{5}+92$$

Express 69\times \frac{7}{5} as a single fraction.

$$\frac{98}{5}-\frac{69\times 7}{5}+92$$

Multiply 69 and 7 to get 483.

$$\frac{98}{5}-\frac{483}{5}+92$$

Since \frac{98}{5} and \frac{483}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{98-483}{5}+92$$

Subtract 483 from 98 to get -385.

$$\frac{-385}{5}+92$$

Divide -385 by 5 to get -77.

$$-77+92$$

Add -77 and 92 to get 15.

$$15$$

Factor

$$3\times 5$$