Solve 10^{3}-10*[2*(7^2-1^8)-3*2^4+2^5]

$$10 ^ { 3 } - 10 \times [ 2 \times ( 7 ^ { 2 } - 1 ^ { 8 } ) - 3 \times 2 ^ { 4 } + 2 ^ { 5 } ]$$

Evaluate

$$200$$

Solution Steps

Calculate 10 to the power of 3 and get 1000.

$$1000-10\left(2\left(7^{2}-1^{8}\right)-3\times 2^{4}+2^{5}\right)$$

Calculate 7 to the power of 2 and get 49.

$$1000-10\left(2\left(49-1^{8}\right)-3\times 2^{4}+2^{5}\right)$$

Calculate 1 to the power of 8 and get 1.

$$1000-10\left(2\left(49-1\right)-3\times 2^{4}+2^{5}\right)$$

Subtract 1 from 49 to get 48.

$$1000-10\left(2\times 48-3\times 2^{4}+2^{5}\right)$$

Multiply 2 and 48 to get 96.

$$1000-10\left(96-3\times 2^{4}+2^{5}\right)$$

Calculate 2 to the power of 4 and get 16.

$$1000-10\left(96-3\times 16+2^{5}\right)$$

Multiply 3 and 16 to get 48.

$$1000-10\left(96-48+2^{5}\right)$$

Subtract 48 from 96 to get 48.

$$1000-10\left(48+2^{5}\right)$$

Calculate 2 to the power of 5 and get 32.

$$1000-10\left(48+32\right)$$

Add 48 and 32 to get 80.

$$1000-10\times 80$$

Multiply 10 and 80 to get 800.

$$1000-800$$

Subtract 800 from 1000 to get 200.

$$200$$

Factor

$$2^{3}\times 5^{2}$$