Solve 10^2-[(2^3)^6/4^9*(9+1)]

$$10 ^ { 2 } - [ \frac { ( 2 ^ { 3 } ) ^ { 6 } } { 4 ^ { 9 } } \cdot ( 9 + 1 ) ]$$

Evaluate

$$90$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 6 to get 18.

$$10^{2}-\frac{2^{18}}{4^{9}}\left(9+1\right)$$

Calculate 10 to the power of 2 and get 100.

$$100-\frac{2^{18}}{4^{9}}\left(9+1\right)$$

Calculate 2 to the power of 18 and get 262144.

$$100-\frac{262144}{4^{9}}\left(9+1\right)$$

Calculate 4 to the power of 9 and get 262144.

$$100-\frac{262144}{262144}\left(9+1\right)$$

Divide 262144 by 262144 to get 1.

$$100-1\left(9+1\right)$$

Add 9 and 1 to get 10.

$$100-1\times 10$$

Multiply 1 and 10 to get 10.

$$100-10$$

Subtract 10 from 100 to get 90.

$$90$$

Factor

$$2\times 3^{2}\times 5$$