Solve 10^2:(+5)+(-6+4)^5:(-4)^2-3^2]

$$10 ^ { 2 } : ( + 5 ) + ( - 6 + 4 ) ^ { 5 } : ( - 4 ) ^ { 2 } - 3 ^ { 2 } ]$$

Evaluate

$$9$$

Solution Steps

Calculate 10 to the power of 2 and get 100.

$$\frac{100}{5}+\frac{\left(-6+4\right)^{5}}{\left(-4\right)^{2}}-3^{2}$$

Divide 100 by 5 to get 20.

$$20+\frac{\left(-6+4\right)^{5}}{\left(-4\right)^{2}}-3^{2}$$

Add -6 and 4 to get -2.

$$20+\frac{\left(-2\right)^{5}}{\left(-4\right)^{2}}-3^{2}$$

Calculate -2 to the power of 5 and get -32.

$$20+\frac{-32}{\left(-4\right)^{2}}-3^{2}$$

Calculate -4 to the power of 2 and get 16.

$$20+\frac{-32}{16}-3^{2}$$

Divide -32 by 16 to get -2.

$$20-2-3^{2}$$

Subtract 2 from 20 to get 18.

$$18-3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$18-9$$

Subtract 9 from 18 to get 9.

$$9$$

Factor

$$3^{2}$$