Solve 10^{2}+11^{2}+12^2=13^2+14^2+22^2

$$10 ^ { 2 } + 11 ^ { 2 } + 12 ^ { 2 } = 13 ^ { 2 } + 14 ^ { 2 } + 22 ^ { 2 }$$

Verify

Solution Steps

Calculate 10 to the power of 2 and get 100.

$$100+11^{2}+12^{2}=13^{2}+14^{2}+22^{2}$$

Calculate 11 to the power of 2 and get 121.

$$100+121+12^{2}=13^{2}+14^{2}+22^{2}$$

Add 100 and 121 to get 221.

$$221+12^{2}=13^{2}+14^{2}+22^{2}$$

Calculate 12 to the power of 2 and get 144.

$$221+144=13^{2}+14^{2}+22^{2}$$

Add 221 and 144 to get 365.

$$365=13^{2}+14^{2}+22^{2}$$

Calculate 13 to the power of 2 and get 169.

$$365=169+14^{2}+22^{2}$$

Calculate 14 to the power of 2 and get 196.

$$365=169+196+22^{2}$$

Add 169 and 196 to get 365.

$$365=365+22^{2}$$

Calculate 22 to the power of 2 and get 484.

$$365=365+484$$

Add 365 and 484 to get 849.

$$365=849$$

Compare 365 and 849.

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