Solve 10^-2+9*10^1+2*10^-1

$$10 ^ { - 2 } + 9 \cdot 10 ^ { 1 } + 2 \cdot 10 ^ { - 1 }$$

Evaluate

$$\frac{9021}{100}=90.21$$

Solution Steps

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$\frac{1}{100}+9\times 10^{1}+2\times 10^{-1}$$

Calculate 10 to the power of 1 and get 10.

$$\frac{1}{100}+9\times 10+2\times 10^{-1}$$

Multiply 9 and 10 to get 90.

$$\frac{1}{100}+90+2\times 10^{-1}$$

Add \frac{1}{100} and 90 to get \frac{9001}{100}.

$$\frac{9001}{100}+2\times 10^{-1}$$

Calculate 10 to the power of -1 and get \frac{1}{10}.

$$\frac{9001}{100}+2\times \frac{1}{10}$$

Multiply 2 and \frac{1}{10} to get \frac{1}{5}.

$$\frac{9001}{100}+\frac{1}{5}$$

Add \frac{9001}{100} and \frac{1}{5} to get \frac{9021}{100}.

$$\frac{9021}{100}$$

Factor

$$\frac{3 \cdot 31 \cdot 97}{2 ^ {2} \cdot 5 ^ {2}} = 90\frac{21}{100} = 90.21$$