Solve 10^-1+(-0,3)^0:11/10

$$10 ^ { - 1 } + ( - 0,3 ) ^ { 0 } : 1 \frac { 1 } { 10 }$$

Evaluate

$$\frac{111}{110}\approx 1,009090909$$

Solution Steps

Calculate 10 to the power of -1 and get \frac{1}{10}.

$$\frac{1}{10}+\frac{\left(-0,3\right)^{0}}{\frac{1\times 10+1}{10}}$$

Calculate -0,3 to the power of 0 and get 1.

$$\frac{1}{10}+\frac{1}{\frac{1\times 10+1}{10}}$$

Multiply 1 and 10 to get 10.

$$\frac{1}{10}+\frac{1}{\frac{10+1}{10}}$$

Add 10 and 1 to get 11.

$$\frac{1}{10}+\frac{1}{\frac{11}{10}}$$

Divide 1 by \frac{11}{10} by multiplying 1 by the reciprocal of \frac{11}{10}.

$$\frac{1}{10}+1\times \frac{10}{11}$$

Multiply 1 and \frac{10}{11} to get \frac{10}{11}.

$$\frac{1}{10}+\frac{10}{11}$$

Add \frac{1}{10} and \frac{10}{11} to get \frac{111}{110}.

$$\frac{111}{110}$$

Factor

$$\frac{3 \cdot 37}{2 \cdot 5 \cdot 11} = 1\frac{1}{110} = 1.009090909090909$$