Solve for a
a=\frac{5}{2e^{4b}}
Solve for b
b=\frac{-\ln(a)+\ln(\frac{5}{2})}{4}
a>0
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4ae^{4b}=10
Swap sides so that all variable terms are on the left hand side.
4e^{4b}a=10
The equation is in standard form.
\frac{4e^{4b}a}{4e^{4b}}=\frac{10}{4e^{4b}}
Divide both sides by 4e^{4b}.
a=\frac{10}{4e^{4b}}
Dividing by 4e^{4b} undoes the multiplication by 4e^{4b}.
a=\frac{5}{2e^{4b}}
Divide 10 by 4e^{4b}.
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