Solve for t
t=\frac{1}{3}\approx 0.333333333
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10=30t
Anything plus zero gives itself.
30t=10
Swap sides so that all variable terms are on the left hand side.
t=\frac{10}{30}
Divide both sides by 30.
t=\frac{1}{3}
Reduce the fraction \frac{10}{30} to lowest terms by extracting and canceling out 10.
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