Solve 10:8+7-sqrt{3}*(64^8)=?

$$10 : 8 + 7 - \sqrt { 3 } \times ( 64 ^ { 8 } ) = ?$$

Evaluate

$$\frac{33}{4}-281474976710656\sqrt{3}\approx -4.875289607 \cdot 10^{14}$$

Solution Steps

Reduce the fraction \frac{10}{8} to lowest terms by extracting and canceling out 2.

$$\frac{5}{4}+7-\sqrt{3}\times 64^{8}$$

Convert 7 to fraction \frac{28}{4}.

$$\frac{5}{4}+\frac{28}{4}-\sqrt{3}\times 64^{8}$$

Since \frac{5}{4} and \frac{28}{4} have the same denominator, add them by adding their numerators.

$$\frac{5+28}{4}-\sqrt{3}\times 64^{8}$$

Add 5 and 28 to get 33.

$$\frac{33}{4}-\sqrt{3}\times 64^{8}$$

Calculate 64 to the power of 8 and get 281474976710656.

$$\frac{33}{4}-\sqrt{3}\times 281474976710656$$

Multiply -1 and 281474976710656 to get -281474976710656.

$$\frac{33}{4}-281474976710656\sqrt{3}$$

Factor

$$\frac{33 - 1125899906842624 \sqrt{3}}{4} = -487528960722114.4$$