Solve for x
x=10\left(\sqrt{3}+2\right)\approx 37.320508076
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10+\sqrt{3}x-2x=0
Subtract 2x from both sides.
\sqrt{3}x-2x=-10
Subtract 10 from both sides. Anything subtracted from zero gives its negation.
\left(\sqrt{3}-2\right)x=-10
Combine all terms containing x.
\frac{\left(\sqrt{3}-2\right)x}{\sqrt{3}-2}=-\frac{10}{\sqrt{3}-2}
Divide both sides by \sqrt{3}-2.
x=-\frac{10}{\sqrt{3}-2}
Dividing by \sqrt{3}-2 undoes the multiplication by \sqrt{3}-2.
x=10\sqrt{3}+20
Divide -10 by \sqrt{3}-2.
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