Solve 10+[15-[12-(9-6+2)]]div{2(4-3)+3}

$$10 + [ 15 - [ 12 - ( 9 - 6 + 2 ) ] ] \div \{ 2 ( 4 - 3 ) + 3 \}$$

Evaluate

$$\frac{58}{5}=11.6$$

Solution Steps

Subtract 6 from 9 to get 3.

$$10+\frac{15-\left(12-\left(3+2\right)\right)}{2\left(4-3\right)+3}$$

Add 3 and 2 to get 5.

$$10+\frac{15-\left(12-5\right)}{2\left(4-3\right)+3}$$

Subtract 5 from 12 to get 7.

$$10+\frac{15-7}{2\left(4-3\right)+3}$$

Subtract 7 from 15 to get 8.

$$10+\frac{8}{2\left(4-3\right)+3}$$

Subtract 3 from 4 to get 1.

$$10+\frac{8}{2\times 1+3}$$

Multiply 2 and 1 to get 2.

$$10+\frac{8}{2+3}$$

Add 2 and 3 to get 5.

$$10+\frac{8}{5}$$

Convert 10 to fraction \frac{50}{5}.

$$\frac{50}{5}+\frac{8}{5}$$

Since \frac{50}{5} and \frac{8}{5} have the same denominator, add them by adding their numerators.

$$\frac{50+8}{5}$$

Add 50 and 8 to get 58.

$$\frac{58}{5}$$

Factor

$$\frac{2 \cdot 29}{5} = 11\frac{3}{5} = 11.6$$