Solve 10+[70-58/2*70-58-43]*2

$$10 + [ \frac { 70 - 58 } { 2 \times 70 - 58 - 43 } ] \times 2$$

Evaluate

$$\frac{138}{13}\approx 10.615384615$$

Solution Steps

Subtract 58 from 70 to get 12.

$$10+\frac{12}{2\times 70-58-43}\times 2$$

Multiply 2 and 70 to get 140.

$$10+\frac{12}{140-58-43}\times 2$$

Subtract 58 from 140 to get 82.

$$10+\frac{12}{82-43}\times 2$$

Subtract 43 from 82 to get 39.

$$10+\frac{12}{39}\times 2$$

Reduce the fraction \frac{12}{39} to lowest terms by extracting and canceling out 3.

$$10+\frac{4}{13}\times 2$$

Express \frac{4}{13}\times 2 as a single fraction.

$$10+\frac{4\times 2}{13}$$

Multiply 4 and 2 to get 8.

$$10+\frac{8}{13}$$

Convert 10 to fraction \frac{130}{13}.

$$\frac{130}{13}+\frac{8}{13}$$

Since \frac{130}{13} and \frac{8}{13} have the same denominator, add them by adding their numerators.

$$\frac{130+8}{13}$$

Add 130 and 8 to get 138.

$$\frac{138}{13}$$

Factor

$$\frac{2 \cdot 3 \cdot 23}{13} = 10\frac{8}{13} = 10.615384615384615$$