Solve 1.8*10^-5=x^2/[0.5]

$$1.8 \times 10 ^ { - 5 } = \frac { x ^ { 2 } } { [ 0.5 ] }$$

Solve for x

$$x=0.003$$

$$x=-0.003$$

Steps by Finding Square Root

Calculate 10 to the power of -5 and get \frac{1}{100000}.

$$1.8\times \frac{1}{100000}=\frac{x^{2}}{0.5}$$

Multiply 1.8 and \frac{1}{100000} to get \frac{9}{500000}.

$$\frac{9}{500000}=\frac{x^{2}}{0.5}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{x^{2}}{0.5}=\frac{9}{500000}$$

Multiply both sides by 0.5.

$$x^{2}=\frac{9}{500000}\times 0.5$$

Multiply \frac{9}{500000} and 0.5 to get \frac{9}{1000000}.

$$x^{2}=\frac{9}{1000000}$$

Take the square root of both sides of the equation.

$$x=\frac{3}{1000} x=-\frac{3}{1000}$$

Steps Using the Quadratic Formula

Calculate 10 to the power of -5 and get \frac{1}{100000}.

$$1.8\times \frac{1}{100000}=\frac{x^{2}}{0.5}$$

Multiply 1.8 and \frac{1}{100000} to get \frac{9}{500000}.

$$\frac{9}{500000}=\frac{x^{2}}{0.5}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{x^{2}}{0.5}=\frac{9}{500000}$$

Subtract \frac{9}{500000} from both sides.

$$\frac{x^{2}}{0.5}-\frac{9}{500000}=0$$

Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.

$$2x^{2}-\frac{9}{500000}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 0 for b, and -\frac{9}{500000} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 2\left(-\frac{9}{500000}\right)}}{2\times 2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 2\left(-\frac{9}{500000}\right)}}{2\times 2}$$

Multiply -4 times 2.

$$x=\frac{0±\sqrt{-8\left(-\frac{9}{500000}\right)}}{2\times 2}$$

Multiply -8 times -\frac{9}{500000}.

$$x=\frac{0±\sqrt{\frac{9}{62500}}}{2\times 2}$$

Take the square root of \frac{9}{62500}.

$$x=\frac{0±\frac{3}{250}}{2\times 2}$$

Multiply 2 times 2.

$$x=\frac{0±\frac{3}{250}}{4}$$

Now solve the equation x=\frac{0±\frac{3}{250}}{4} when ± is plus.

$$x=\frac{3}{1000}$$

Now solve the equation x=\frac{0±\frac{3}{250}}{4} when ± is minus.

$$x=-\frac{3}{1000}$$

The equation is now solved.

$$x=\frac{3}{1000} x=-\frac{3}{1000}$$