Solve 1.8*10^-2*(10^-2+1)

$$1.8 \cdot 10 ^ { - 2 } \cdot ( 10 ^ { - 2 } + 1 )$$

Evaluate

$$0.01818$$

Solution Steps

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$1.8\times \frac{1}{100}\left(10^{-2}+1\right)$$

Multiply 1.8 and \frac{1}{100} to get \frac{9}{500}.

$$\frac{9}{500}\left(10^{-2}+1\right)$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$\frac{9}{500}\left(\frac{1}{100}+1\right)$$

Add \frac{1}{100} and 1 to get \frac{101}{100}.

$$\frac{9}{500}\times \frac{101}{100}$$

Multiply \frac{9}{500} and \frac{101}{100} to get \frac{909}{50000}.

$$\frac{909}{50000}$$

Factor

$$\frac{101 \cdot 3 ^ {2}}{2 ^ {4} \cdot 5 ^ {5}} = 0.01818$$