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-7.5x^{2}-6x+1.5=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}-4\left(-7.5\right)\times 1.5}}{2\left(-7.5\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -7.5 for a, -6 for b, and 1.5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-6\right)±\sqrt{36-4\left(-7.5\right)\times 1.5}}{2\left(-7.5\right)}
Square -6.
x=\frac{-\left(-6\right)±\sqrt{36+30\times 1.5}}{2\left(-7.5\right)}
Multiply -4 times -7.5.
x=\frac{-\left(-6\right)±\sqrt{36+45}}{2\left(-7.5\right)}
Multiply 30 times 1.5.
x=\frac{-\left(-6\right)±\sqrt{81}}{2\left(-7.5\right)}
Add 36 to 45.
x=\frac{-\left(-6\right)±9}{2\left(-7.5\right)}
Take the square root of 81.
x=\frac{6±9}{2\left(-7.5\right)}
The opposite of -6 is 6.
x=\frac{6±9}{-15}
Multiply 2 times -7.5.
x=\frac{15}{-15}
Now solve the equation x=\frac{6±9}{-15} when ± is plus. Add 6 to 9.
x=-1
Divide 15 by -15.
x=-\frac{3}{-15}
Now solve the equation x=\frac{6±9}{-15} when ± is minus. Subtract 9 from 6.
x=\frac{1}{5}
Reduce the fraction \frac{-3}{-15} to lowest terms by extracting and canceling out 3.
x=-1 x=\frac{1}{5}
The equation is now solved.
-7.5x^{2}-6x+1.5=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
-7.5x^{2}-6x+1.5-1.5=-1.5
Subtract 1.5 from both sides of the equation.
-7.5x^{2}-6x=-1.5
Subtracting 1.5 from itself leaves 0.
\frac{-7.5x^{2}-6x}{-7.5}=-\frac{1.5}{-7.5}
Divide both sides of the equation by -7.5, which is the same as multiplying both sides by the reciprocal of the fraction.
x^{2}+\left(-\frac{6}{-7.5}\right)x=-\frac{1.5}{-7.5}
Dividing by -7.5 undoes the multiplication by -7.5.
x^{2}+0.8x=-\frac{1.5}{-7.5}
Divide -6 by -7.5 by multiplying -6 by the reciprocal of -7.5.
x^{2}+0.8x=0.2
Divide -1.5 by -7.5 by multiplying -1.5 by the reciprocal of -7.5.
x^{2}+0.8x+0.4^{2}=0.2+0.4^{2}
Divide 0.8, the coefficient of the x term, by 2 to get 0.4. Then add the square of 0.4 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+0.8x+0.16=0.2+0.16
Square 0.4 by squaring both the numerator and the denominator of the fraction.
x^{2}+0.8x+0.16=0.36
Add 0.2 to 0.16 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x+0.4\right)^{2}=0.36
Factor x^{2}+0.8x+0.16. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+0.4\right)^{2}}=\sqrt{0.36}
Take the square root of both sides of the equation.
x+0.4=\frac{3}{5} x+0.4=-\frac{3}{5}
Simplify.
x=\frac{1}{5} x=-1
Subtract 0.4 from both sides of the equation.