Solve 1.3+[6+2*(2^34+3*2)-7.2]+9div3

$$1.3 + [ 6 + 2 \cdot ( 2 ^ { 3 } 4 + 3 \cdot 2 ) - 7.2 ] + 9 \div 3$$

Evaluate

$$79.1$$

Solution Steps

Add 1.3 and 6 to get 7.3.

$$7.3+2\left(2^{3}\times 4+3\times 2\right)-7.2+\frac{9}{3}$$

Calculate 2 to the power of 3 and get 8.

$$7.3+2\left(8\times 4+3\times 2\right)-7.2+\frac{9}{3}$$

Multiply 8 and 4 to get 32.

$$7.3+2\left(32+3\times 2\right)-7.2+\frac{9}{3}$$

Multiply 3 and 2 to get 6.

$$7.3+2\left(32+6\right)-7.2+\frac{9}{3}$$

Add 32 and 6 to get 38.

$$7.3+2\times 38-7.2+\frac{9}{3}$$

Multiply 2 and 38 to get 76.

$$7.3+76-7.2+\frac{9}{3}$$

Add 7.3 and 76 to get 83.3.

$$83.3-7.2+\frac{9}{3}$$

Subtract 7.2 from 83.3 to get 76.1.

$$76.1+\frac{9}{3}$$

Divide 9 by 3 to get 3.

$$76.1+3$$

Add 76.1 and 3 to get 79.1.

$$79.1$$

Factor

$$\frac{7 \cdot 113}{2 \cdot 5} = 79\frac{1}{10} = 79.1$$