Solve 1.29*[25/5+(346.23-293,15)^2]*6,9/34

$$1.29 \times [ 25 / 5 + ( 346.23 - 293,15 ) ^ { 2 } ] \times 6,9 / 34$$

Evaluate

$$\frac{7850922327}{10625000}\approx 738.910336659$$

Solution Steps

Divide 25 by 5 to get 5.

$$1.29\left(5+\left(346.23-293.15\right)^{2}\right)\times \frac{6.9}{34}$$

Subtract 293.15 from 346.23 to get 53.08.

$$1.29\left(5+53.08^{2}\right)\times \frac{6.9}{34}$$

Calculate 53.08 to the power of 2 and get 2817.4864.

$$1.29\left(5+2817.4864\right)\times \frac{6.9}{34}$$

Add 5 and 2817.4864 to get 2822.4864.

$$1.29\times 2822.4864\times \frac{6.9}{34}$$

Multiply 1.29 and 2822.4864 to get 3641.007456.

$$3641.007456\times \frac{6.9}{34}$$

Expand \frac{6.9}{34} by multiplying both numerator and the denominator by 10.

$$3641.007456\times \frac{69}{340}$$

Multiply 3641.007456 and \frac{69}{340} to get \frac{7850922327}{10625000}.

$$\frac{7850922327}{10625000}$$

Factor

$$\frac{43 \cdot 4261 \cdot 3 ^ {4} \cdot 23 ^ {2}}{17 \cdot 2 ^ {3} \cdot 5 ^ {7}} = 738\frac{9672327}{10625000} = 738.9103366588236$$