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x\left(1.25x+27.778\right)=0
Factor out x.
x=0 x=-\frac{13889}{625}
To find equation solutions, solve x=0 and \frac{5x}{4}+27.778=0.
1.25x^{2}+27.778x=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-27.778±\sqrt{27.778^{2}}}{2\times 1.25}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1.25 for a, 27.778 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-27.778±\frac{13889}{500}}{2\times 1.25}
Take the square root of 27.778^{2}.
x=\frac{-27.778±\frac{13889}{500}}{2.5}
Multiply 2 times 1.25.
x=\frac{0}{2.5}
Now solve the equation x=\frac{-27.778±\frac{13889}{500}}{2.5} when ± is plus. Add -27.778 to \frac{13889}{500} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
x=0
Divide 0 by 2.5 by multiplying 0 by the reciprocal of 2.5.
x=-\frac{\frac{13889}{250}}{2.5}
Now solve the equation x=\frac{-27.778±\frac{13889}{500}}{2.5} when ± is minus. Subtract \frac{13889}{500} from -27.778 by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.
x=-\frac{13889}{625}
Divide -\frac{13889}{250} by 2.5 by multiplying -\frac{13889}{250} by the reciprocal of 2.5.
x=0 x=-\frac{13889}{625}
The equation is now solved.
1.25x^{2}+27.778x=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{1.25x^{2}+27.778x}{1.25}=\frac{0}{1.25}
Divide both sides of the equation by 1.25, which is the same as multiplying both sides by the reciprocal of the fraction.
x^{2}+\frac{27.778}{1.25}x=\frac{0}{1.25}
Dividing by 1.25 undoes the multiplication by 1.25.
x^{2}+22.2224x=\frac{0}{1.25}
Divide 27.778 by 1.25 by multiplying 27.778 by the reciprocal of 1.25.
x^{2}+22.2224x=0
Divide 0 by 1.25 by multiplying 0 by the reciprocal of 1.25.
x^{2}+22.2224x+11.1112^{2}=11.1112^{2}
Divide 22.2224, the coefficient of the x term, by 2 to get 11.1112. Then add the square of 11.1112 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+22.2224x+123.45876544=123.45876544
Square 11.1112 by squaring both the numerator and the denominator of the fraction.
\left(x+11.1112\right)^{2}=123.45876544
Factor x^{2}+22.2224x+123.45876544. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+11.1112\right)^{2}}=\sqrt{123.45876544}
Take the square root of both sides of the equation.
x+11.1112=\frac{13889}{1250} x+11.1112=-\frac{13889}{1250}
Simplify.
x=0 x=-\frac{13889}{625}
Subtract 11.1112 from both sides of the equation.