Solve 1.2(2t-3)leq2.3(t-1)

$$1.2 ( 2 t - 3 ) \leq 2.3 ( t - 1 )$$

Solve for t

$$t\leq 13$$

Solution Steps

Use the distributive property to multiply 1.2 by 2t-3.

$$2.4t-3.6\leq 2.3\left(t-1\right)$$

Use the distributive property to multiply 2.3 by t-1.

$$2.4t-3.6\leq 2.3t-2.3$$

Subtract 2.3t from both sides.

$$2.4t-3.6-2.3t\leq -2.3$$

Combine 2.4t and -2.3t to get 0.1t.

$$0.1t-3.6\leq -2.3$$

Add 3.6 to both sides.

$$0.1t\leq -2.3+3.6$$

Add -2.3 and 3.6 to get 1.3.

$$0.1t\leq 1.3$$

Divide both sides by 0.1. Since 0.1 is positive, the inequality direction remains the same.

$$t\leq \frac{1.3}{0.1}$$

Expand \frac{1.3}{0.1} by multiplying both numerator and the denominator by 10. Anything divided by one gives itself.

$$t\leq 13$$