Solve 1.12x+0.70y+0.36z=3.92

$$1.12 x + 0.70 y + 0.36 z = 3.92$$

Solve for x

$$x=-\frac{5y}{8}-\frac{9z}{28}+3.5$$

Steps for Solving Linear Equation

Subtract 0.7y from both sides.

$$1.12x+0.36z=3.92-0.7y$$

Subtract 0.36z from both sides.

$$1.12x=3.92-0.7y-0.36z$$

The equation is in standard form.

$$1.12x=-\frac{7y}{10}-\frac{9z}{25}+3.92$$

Divide both sides of the equation by 1.12, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{1.12x}{1.12}=\frac{-\frac{7y}{10}-\frac{9z}{25}+3.92}{1.12}$$

Dividing by 1.12 undoes the multiplication by 1.12.

$$x=\frac{-\frac{7y}{10}-\frac{9z}{25}+3.92}{1.12}$$

Divide 3.92-\frac{7y}{10}-\frac{9z}{25} by 1.12 by multiplying 3.92-\frac{7y}{10}-\frac{9z}{25} by the reciprocal of 1.12.

$$x=-\frac{5y}{8}-\frac{9z}{28}+\frac{7}{2}$$

Solve for y

$$y=-\frac{8x}{5}-\frac{18z}{35}+5.6$$

Steps for Solving Linear Equation

Subtract 1.12x from both sides.

$$0.7y+0.36z=3.92-1.12x$$

Subtract 0.36z from both sides.

$$0.7y=3.92-1.12x-0.36z$$

The equation is in standard form.

$$0.7y=\frac{98-9z-28x}{25}$$

Divide both sides of the equation by 0.7, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0.7y}{0.7}=\frac{98-9z-28x}{0.7\times 25}$$

Dividing by 0.7 undoes the multiplication by 0.7.

$$y=\frac{98-9z-28x}{0.7\times 25}$$

Divide \frac{98-28x-9z}{25} by 0.7 by multiplying \frac{98-28x-9z}{25} by the reciprocal of 0.7.

$$y=-\frac{8x}{5}-\frac{18z}{35}+\frac{28}{5}$$