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1.11x-5=\frac{\left(x+25\right)\sqrt{3}}{\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{x+25}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
1.11x-5=\frac{\left(x+25\right)\sqrt{3}}{3}
The square of \sqrt{3} is 3.
1.11x-5=\frac{x\sqrt{3}+25\sqrt{3}}{3}
Use the distributive property to multiply x+25 by \sqrt{3}.
1.11x-5-\frac{x\sqrt{3}+25\sqrt{3}}{3}=0
Subtract \frac{x\sqrt{3}+25\sqrt{3}}{3} from both sides.
1.11x-\frac{x\sqrt{3}+25\sqrt{3}}{3}=5
Add 5 to both sides. Anything plus zero gives itself.
3.33x-\left(x\sqrt{3}+25\sqrt{3}\right)=15
Multiply both sides of the equation by 3.
3.33x-x\sqrt{3}-25\sqrt{3}=15
To find the opposite of x\sqrt{3}+25\sqrt{3}, find the opposite of each term.
3.33x-x\sqrt{3}=15+25\sqrt{3}
Add 25\sqrt{3} to both sides.
\left(3.33-\sqrt{3}\right)x=15+25\sqrt{3}
Combine all terms containing x.
\left(3.33-\sqrt{3}\right)x=25\sqrt{3}+15
The equation is in standard form.
\frac{\left(3.33-\sqrt{3}\right)x}{3.33-\sqrt{3}}=\frac{25\sqrt{3}+15}{3.33-\sqrt{3}}
Divide both sides by 3.33-\sqrt{3}.
x=\frac{25\sqrt{3}+15}{3.33-\sqrt{3}}
Dividing by 3.33-\sqrt{3} undoes the multiplication by 3.33-\sqrt{3}.
x=\frac{327500\sqrt{3}+416500}{26963}
Divide 15+25\sqrt{3} by 3.33-\sqrt{3}.