Solve 1.02div0.0188-1.02

$$1.02 \div 0.0188-1.02$$

Evaluate

$$\frac{125103}{2350}\approx 53.235319149$$

Solution Steps

Expand \frac{1.02}{0.0188} by multiplying both numerator and the denominator by 10000.

$$\frac{10200}{188}-1.02$$

Reduce the fraction \frac{10200}{188} to lowest terms by extracting and canceling out 4.

$$\frac{2550}{47}-1.02$$

Convert decimal number 1.02 to fraction \frac{102}{100}. Reduce the fraction \frac{102}{100} to lowest terms by extracting and canceling out 2.

$$\frac{2550}{47}-\frac{51}{50}$$

Least common multiple of 47 and 50 is 2350. Convert \frac{2550}{47} and \frac{51}{50} to fractions with denominator 2350.

$$\frac{127500}{2350}-\frac{2397}{2350}$$

Since \frac{127500}{2350} and \frac{2397}{2350} have the same denominator, subtract them by subtracting their numerators.

$$\frac{127500-2397}{2350}$$

Subtract 2397 from 127500 to get 125103.

$$\frac{125103}{2350}$$

Factor

$$\frac{3 \cdot 11 \cdot 17 \cdot 223}{2 \cdot 47 \cdot 5 ^ {2}} = 53\frac{553}{2350} = 53.23531914893617$$