Solve for x
x\in (-\infty,-\frac{1}{5}]\cup [\frac{1}{5},\infty)
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-1+25x^{2}\geq 0
Multiply the inequality by -1 to make the coefficient of the highest power in 1-25x^{2} positive. Since -1 is negative, the inequality direction is changed.
x^{2}\geq \frac{1}{25}
Add \frac{1}{25} to both sides.
x^{2}\geq \left(\frac{1}{5}\right)^{2}
Calculate the square root of \frac{1}{25} and get \frac{1}{5}. Rewrite \frac{1}{25} as \left(\frac{1}{5}\right)^{2}.
|x|\geq \frac{1}{5}
Inequality holds for |x|\geq \frac{1}{5}.
x\leq -\frac{1}{5}\text{; }x\geq \frac{1}{5}
Rewrite |x|\geq \frac{1}{5} as x\leq -\frac{1}{5}\text{; }x\geq \frac{1}{5}.
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