Solve 1-(4/12+3/18)

$$1-( \frac{ 4 }{ 12 } + \frac{ 3 }{ 18 } )$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.

$$1-\left(\frac{1}{3}+\frac{3}{18}\right)$$

Reduce the fraction \frac{3}{18} to lowest terms by extracting and canceling out 3.

$$1-\left(\frac{1}{3}+\frac{1}{6}\right)$$

Least common multiple of 3 and 6 is 6. Convert \frac{1}{3} and \frac{1}{6} to fractions with denominator 6.

$$1-\left(\frac{2}{6}+\frac{1}{6}\right)$$

Since \frac{2}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$1-\frac{2+1}{6}$$

Add 2 and 1 to get 3.

$$1-\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$1-\frac{1}{2}$$

Convert 1 to fraction \frac{2}{2}.

$$\frac{2}{2}-\frac{1}{2}$$

Since \frac{2}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-1}{2}$$

Subtract 1 from 2 to get 1.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$