Solve 1-(35/48+1/8)

$$1-( \frac{ 35 }{ 48 } + \frac{ 1 }{ 8 } )$$

Evaluate

$$\frac{7}{48}\approx 0.145833333$$

Solution Steps

Least common multiple of 48 and 8 is 48. Convert \frac{35}{48} and \frac{1}{8} to fractions with denominator 48.

$$1-\left(\frac{35}{48}+\frac{6}{48}\right)$$

Since \frac{35}{48} and \frac{6}{48} have the same denominator, add them by adding their numerators.

$$1-\frac{35+6}{48}$$

Add 35 and 6 to get 41.

$$1-\frac{41}{48}$$

Convert 1 to fraction \frac{48}{48}.

$$\frac{48}{48}-\frac{41}{48}$$

Since \frac{48}{48} and \frac{41}{48} have the same denominator, subtract them by subtracting their numerators.

$$\frac{48-41}{48}$$

Subtract 41 from 48 to get 7.

$$\frac{7}{48}$$

Factor

$$\frac{7}{2 ^ {4} \cdot 3} = 0.14583333333333334$$