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1-\left(9\left(\sqrt{5}\right)^{2}-6\sqrt{5}+1\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(3\sqrt{5}-1\right)^{2}.
1-\left(9\times 5-6\sqrt{5}+1\right)
The square of \sqrt{5} is 5.
1-\left(45-6\sqrt{5}+1\right)
Multiply 9 and 5 to get 45.
1-\left(46-6\sqrt{5}\right)
Add 45 and 1 to get 46.
1-46+6\sqrt{5}
To find the opposite of 46-6\sqrt{5}, find the opposite of each term.
-45+6\sqrt{5}
Subtract 46 from 1 to get -45.
1-\left(9\left(\sqrt{5}\right)^{2}-6\sqrt{5}+1\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(3\sqrt{5}-1\right)^{2}.
1-\left(9\times 5-6\sqrt{5}+1\right)
The square of \sqrt{5} is 5.
1-\left(45-6\sqrt{5}+1\right)
Multiply 9 and 5 to get 45.
1-\left(46-6\sqrt{5}\right)
Add 45 and 1 to get 46.
1-46+6\sqrt{5}
To find the opposite of 46-6\sqrt{5}, find the opposite of each term.
-45+6\sqrt{5}
Subtract 46 from 1 to get -45.