Solve 1-1/3+2/9=

$$1- \frac{ 1 }{ 3 } + \frac{ 2 }{ 9 } =$$

Evaluate

$$\frac{8}{9}\approx 0.888888889$$

Solution Steps

Convert 1 to fraction \frac{3}{3}.

$$\frac{3}{3}-\frac{1}{3}+\frac{2}{9}$$

Since \frac{3}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-1}{3}+\frac{2}{9}$$

Subtract 1 from 3 to get 2.

$$\frac{2}{3}+\frac{2}{9}$$

Least common multiple of 3 and 9 is 9. Convert \frac{2}{3} and \frac{2}{9} to fractions with denominator 9.

$$\frac{6}{9}+\frac{2}{9}$$

Since \frac{6}{9} and \frac{2}{9} have the same denominator, add them by adding their numerators.

$$\frac{6+2}{9}$$

Add 6 and 2 to get 8.

$$\frac{8}{9}$$

Factor

$$\frac{2 ^ {3}}{3 ^ {2}} = 0.8888888888888888$$