Solve 1,25*(-2)^3-[(-4)div(-2/3)^2+1]+(-1)

$$1,25 \times ( - 2 ) ^ { 3 } - [ ( - 4 ) \div ( - \frac { 2 } { 3 } ) ^ { 2 } + 1 ] + ( - 1 )$$

Evaluate

$$-3$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$1,25\left(-8\right)-\left(\frac{-4}{\left(-\frac{2}{3}\right)^{2}}+1\right)-1$$

Multiply 1,25 and -8 to get -10.

$$-10-\left(\frac{-4}{\left(-\frac{2}{3}\right)^{2}}+1\right)-1$$

Calculate -\frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$-10-\left(\frac{-4}{\frac{4}{9}}+1\right)-1$$

Divide -4 by \frac{4}{9} by multiplying -4 by the reciprocal of \frac{4}{9}.

$$-10-\left(-4\times \frac{9}{4}+1\right)-1$$

Multiply -4 times \frac{9}{4}.

$$-10-\left(-9+1\right)-1$$

Add -9 and 1 to get -8.

$$-10-\left(-8\right)-1$$

The opposite of -8 is 8.

$$-10+8-1$$

Add -10 and 8 to get -2.

$$-2-1$$

Subtract 1 from -2 to get -3.

$$-3$$

Factor

$$-3$$