Solve 1+20-5*7/3+7-2*12/2

$$1+20-5 \times \frac{ 7 }{ 3 } +7-2 \times \frac{ 12 }{ 2 }$$

Evaluate

$$\frac{13}{3}\approx 4.333333333$$

Solution Steps

Add 1 and 20 to get 21.

$$21-5\times \frac{7}{3}+7-2\times \frac{12}{2}$$

Express 5\times \frac{7}{3} as a single fraction.

$$21-\frac{5\times 7}{3}+7-2\times \frac{12}{2}$$

Multiply 5 and 7 to get 35.

$$21-\frac{35}{3}+7-2\times \frac{12}{2}$$

Convert 21 to fraction \frac{63}{3}.

$$\frac{63}{3}-\frac{35}{3}+7-2\times \frac{12}{2}$$

Since \frac{63}{3} and \frac{35}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{63-35}{3}+7-2\times \frac{12}{2}$$

Subtract 35 from 63 to get 28.

$$\frac{28}{3}+7-2\times \frac{12}{2}$$

Convert 7 to fraction \frac{21}{3}.

$$\frac{28}{3}+\frac{21}{3}-2\times \frac{12}{2}$$

Since \frac{28}{3} and \frac{21}{3} have the same denominator, add them by adding their numerators.

$$\frac{28+21}{3}-2\times \frac{12}{2}$$

Add 28 and 21 to get 49.

$$\frac{49}{3}-2\times \frac{12}{2}$$

Divide 12 by 2 to get 6.

$$\frac{49}{3}-2\times 6$$

Multiply 2 and 6 to get 12.

$$\frac{49}{3}-12$$

Convert 12 to fraction \frac{36}{3}.

$$\frac{49}{3}-\frac{36}{3}$$

Since \frac{49}{3} and \frac{36}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-36}{3}$$

Subtract 36 from 49 to get 13.

$$\frac{13}{3}$$

Factor

$$\frac{13}{3} = 4\frac{1}{3} = 4.333333333333333$$