Solve 1+1/1+frac{1{3}}

$$1+ \frac{ 1 }{ 1+ \frac{ 1 }{ 3 } }$$

Evaluate

$$\frac{7}{4}=1.75$$

Solution Steps

Convert 1 to fraction \frac{3}{3}.

$$1+\frac{1}{\frac{3}{3}+\frac{1}{3}}$$

Since \frac{3}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$1+\frac{1}{\frac{3+1}{3}}$$

Add 3 and 1 to get 4.

$$1+\frac{1}{\frac{4}{3}}$$

Divide 1 by \frac{4}{3} by multiplying 1 by the reciprocal of \frac{4}{3}.

$$1+1\times \frac{3}{4}$$

Multiply 1 and \frac{3}{4} to get \frac{3}{4}.

$$1+\frac{3}{4}$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{4}{4}+\frac{3}{4}$$

Since \frac{4}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{4+3}{4}$$

Add 4 and 3 to get 7.

$$\frac{7}{4}$$

Factor

$$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$$