Solve for x
x=2\left(y-3\right)
Solve for y
y=\frac{x+6}{2}
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1x+6=2y
Add 2y to both sides. Anything plus zero gives itself.
1x=2y-6
Subtract 6 from both sides.
x=2y-6
Reorder the terms.
-2y+6=-x
Subtract 1x from both sides. Anything subtracted from zero gives its negation.
-2y=-x-6
Subtract 6 from both sides.
\frac{-2y}{-2}=\frac{-x-6}{-2}
Divide both sides by -2.
y=\frac{-x-6}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{x}{2}+3
Divide -x-6 by -2.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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