Solve 1x^2=10-x

$$1 x ^ { 2 } = 10 - x$$

Solve for x

$$x = \frac{\sqrt{41} - 1}{2} \approx 2.701562119$$

$$x=\frac{-\sqrt{41}-1}{2}\approx -3.701562119$$

Steps Using the Quadratic Formula

Subtract 10 from both sides.

$$1x^{2}-10=-x$$

Add x to both sides.

$$1x^{2}-10+x=0$$

Reorder the terms.

$$x^{2}+x-10=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 1 for b, and -10 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-1±\sqrt{1^{2}-4\left(-10\right)}}{2}$$

Square 1.

$$x=\frac{-1±\sqrt{1-4\left(-10\right)}}{2}$$

Multiply -4 times -10.

$$x=\frac{-1±\sqrt{1+40}}{2}$$

Add 1 to 40.

$$x=\frac{-1±\sqrt{41}}{2}$$

Now solve the equation x=\frac{-1±\sqrt{41}}{2} when ± is plus. Add -1 to \sqrt{41}.

$$x=\frac{\sqrt{41}-1}{2}$$

Now solve the equation x=\frac{-1±\sqrt{41}}{2} when ± is minus. Subtract \sqrt{41} from -1.

$$x=\frac{-\sqrt{41}-1}{2}$$

The equation is now solved.

$$x=\frac{\sqrt{41}-1}{2} x=\frac{-\sqrt{41}-1}{2}$$

Steps for Completing the Square

Add x to both sides.

$$1x^{2}+x=10$$

Reorder the terms.

$$x^{2}+x=10$$

Divide 1, the coefficient of the x term, by 2 to get \frac{1}{2}. Then add the square of \frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}+x+\left(\frac{1}{2}\right)^{2}=10+\left(\frac{1}{2}\right)^{2}$$

Square \frac{1}{2} by squaring both the numerator and the denominator of the fraction.

$$x^{2}+x+\frac{1}{4}=10+\frac{1}{4}$$

Add 10 to \frac{1}{4}.

$$x^{2}+x+\frac{1}{4}=\frac{41}{4}$$

Factor x^{2}+x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+\frac{1}{2}\right)^{2}=\frac{41}{4}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x+\frac{1}{2}\right)^{2}}=\sqrt{\frac{41}{4}}$$

Simplify.

$$x+\frac{1}{2}=\frac{\sqrt{41}}{2} x+\frac{1}{2}=-\frac{\sqrt{41}}{2}$$

Subtract \frac{1}{2} from both sides of the equation.

$$x=\frac{\sqrt{41}-1}{2} x=\frac{-\sqrt{41}-1}{2}$$