Solve for x
x=96-10y^{2}
Solve for y (complex solution)
y=-\frac{\sqrt{960-10x}}{10}
y=\frac{\sqrt{960-10x}}{10}
Solve for y
y=\frac{\sqrt{960-10x}}{10}
y=-\frac{\sqrt{960-10x}}{10}\text{, }x\leq 96
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1x=96-10y^{2}
Subtract 10y^{2} from both sides.
x=-10y^{2}+96
Reorder the terms.
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