Solve 1nx+2x^2-5=0

$$1 n x + 2 x ^ { 2 } - 5 = 0$$

Solve for n

$$n=-2x+\frac{5}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.

$$1nx-5=-2x^{2}$$

Add 5 to both sides.

$$1nx=-2x^{2}+5$$

Reorder the terms.

$$nx=-2x^{2}+5$$

The equation is in standard form.

$$xn=5-2x^{2}$$

Divide both sides by x.

$$\frac{xn}{x}=\frac{5-2x^{2}}{x}$$

Dividing by x undoes the multiplication by x.

$$n=\frac{5-2x^{2}}{x}$$

Divide -2x^{2}+5 by x.

$$n=-2x+\frac{5}{x}$$

Solve for x

$$x=\frac{\sqrt{n^{2}+40}-n}{4}$$

$$x=\frac{-\sqrt{n^{2}+40}-n}{4}$$