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\left(3+n-c\right)\left(3+n+c\right)
Rewrite n^{2}+6n+9-c^{2} as \left(3+n\right)^{2}-c^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(n-c+3\right)\left(n+c+3\right)
Reorder the terms.