Solve for c
c=1-3q
Solve for q
q=\frac{1-c}{3}
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2-2c-4q=1-q-c
Multiply both sides of the equation by 2.
2-2c-4q+c=1-q
Add c to both sides.
2-c-4q=1-q
Combine -2c and c to get -c.
-c-4q=1-q-2
Subtract 2 from both sides.
-c-4q=-1-q
Subtract 2 from 1 to get -1.
-c=-1-q+4q
Add 4q to both sides.
-c=-1+3q
Combine -q and 4q to get 3q.
-c=3q-1
The equation is in standard form.
\frac{-c}{-1}=\frac{3q-1}{-1}
Divide both sides by -1.
c=\frac{3q-1}{-1}
Dividing by -1 undoes the multiplication by -1.
c=1-3q
Divide -1+3q by -1.
2-2c-4q=1-q-c
Multiply both sides of the equation by 2.
2-2c-4q+q=1-c
Add q to both sides.
2-2c-3q=1-c
Combine -4q and q to get -3q.
-2c-3q=1-c-2
Subtract 2 from both sides.
-2c-3q=-1-c
Subtract 2 from 1 to get -1.
-3q=-1-c+2c
Add 2c to both sides.
-3q=-1+c
Combine -c and 2c to get c.
-3q=c-1
The equation is in standard form.
\frac{-3q}{-3}=\frac{c-1}{-3}
Divide both sides by -3.
q=\frac{c-1}{-3}
Dividing by -3 undoes the multiplication by -3.
q=\frac{1-c}{3}
Divide -1+c by -3.
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Limits
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