Solve 1-31/5+1021/25+(-47/10)

$$1 - 3 \frac { 1 } { 5 } + 10 \frac { 21 } { 25 } + ( - 4 \frac { 7 } { 10 } )$$

Evaluate

$$\frac{197}{50}=3.94$$

Solution Steps

Multiply 3 and 5 to get 15.

$$1-\frac{15+1}{5}+\frac{10\times 25+21}{25}-\frac{4\times 10+7}{10}$$

Add 15 and 1 to get 16.

$$1-\frac{16}{5}+\frac{10\times 25+21}{25}-\frac{4\times 10+7}{10}$$

Convert 1 to fraction \frac{5}{5}.

$$\frac{5}{5}-\frac{16}{5}+\frac{10\times 25+21}{25}-\frac{4\times 10+7}{10}$$

Since \frac{5}{5} and \frac{16}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-16}{5}+\frac{10\times 25+21}{25}-\frac{4\times 10+7}{10}$$

Subtract 16 from 5 to get -11.

$$-\frac{11}{5}+\frac{10\times 25+21}{25}-\frac{4\times 10+7}{10}$$

Multiply 10 and 25 to get 250.

$$-\frac{11}{5}+\frac{250+21}{25}-\frac{4\times 10+7}{10}$$

Add 250 and 21 to get 271.

$$-\frac{11}{5}+\frac{271}{25}-\frac{4\times 10+7}{10}$$

Least common multiple of 5 and 25 is 25. Convert -\frac{11}{5} and \frac{271}{25} to fractions with denominator 25.

$$-\frac{55}{25}+\frac{271}{25}-\frac{4\times 10+7}{10}$$

Since -\frac{55}{25} and \frac{271}{25} have the same denominator, add them by adding their numerators.

$$\frac{-55+271}{25}-\frac{4\times 10+7}{10}$$

Add -55 and 271 to get 216.

$$\frac{216}{25}-\frac{4\times 10+7}{10}$$

Multiply 4 and 10 to get 40.

$$\frac{216}{25}-\frac{40+7}{10}$$

Add 40 and 7 to get 47.

$$\frac{216}{25}-\frac{47}{10}$$

Least common multiple of 25 and 10 is 50. Convert \frac{216}{25} and \frac{47}{10} to fractions with denominator 50.

$$\frac{432}{50}-\frac{235}{50}$$

Since \frac{432}{50} and \frac{235}{50} have the same denominator, subtract them by subtracting their numerators.

$$\frac{432-235}{50}$$

Subtract 235 from 432 to get 197.

$$\frac{197}{50}$$

Factor

$$\frac{197}{2 \cdot 5 ^ {2}} = 3\frac{47}{50} = 3.94$$