Solve 1-19/16+11/12=

$$1 - 1 \frac { 9 } { 16 } + \frac { 11 } { 12 } =$$

Evaluate

$$\frac{17}{48}\approx 0.354166667$$

Solution Steps

Multiply 1 and 16 to get 16.

$$1-\frac{16+9}{16}+\frac{11}{12}$$

Add 16 and 9 to get 25.

$$1-\frac{25}{16}+\frac{11}{12}$$

Convert 1 to fraction \frac{16}{16}.

$$\frac{16}{16}-\frac{25}{16}+\frac{11}{12}$$

Since \frac{16}{16} and \frac{25}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-25}{16}+\frac{11}{12}$$

Subtract 25 from 16 to get -9.

$$-\frac{9}{16}+\frac{11}{12}$$

Least common multiple of 16 and 12 is 48. Convert -\frac{9}{16} and \frac{11}{12} to fractions with denominator 48.

$$-\frac{27}{48}+\frac{44}{48}$$

Since -\frac{27}{48} and \frac{44}{48} have the same denominator, add them by adding their numerators.

$$\frac{-27+44}{48}$$

Add -27 and 44 to get 17.

$$\frac{17}{48}$$

Factor

$$\frac{17}{2 ^ {4} \cdot 3} = 0.3541666666666667$$