Solve 1--3+{-5-[-6+(4-3)-(1-2)]-5}

$$1 - - 3 + \{ - 5 - [ - 6 + ( 4 - 3 ) - ( 1 - 2 ) ] - 5 \}$$

Evaluate

$$-2$$

Solution Steps

The opposite of -3 is 3.

$$1+3+-5-\left(-6+4-3-\left(1-2\right)\right)-5$$

Add 1 and 3 to get 4.

$$4+-5-\left(-6+4-3-\left(1-2\right)\right)-5$$

Add -6 and 4 to get -2.

$$4+-5-\left(-2-3-\left(1-2\right)\right)-5$$

Subtract 3 from -2 to get -5.

$$4+-5-\left(-5-\left(1-2\right)\right)-5$$

Subtract 2 from 1 to get -1.

$$4+-5-\left(-5-\left(-1\right)\right)-5$$

The opposite of -1 is 1.

$$4+-5-\left(-5+1\right)-5$$

Add -5 and 1 to get -4.

$$4+-5-\left(-4\right)-5$$

The opposite of -4 is 4.

$$4-5+4-5$$

Add -5 and 4 to get -1.

$$4-1-5$$

Subtract 1 from 4 to get 3.

$$3-5$$

Subtract 5 from 3 to get -2.

$$-2$$

Factor

$$-2$$