Solve 1-(4-2)!:5+(12-2

$$1 - ( 4 - 2 ) ! : 5 + ( 12 - 2$$

Evaluate

$$\frac{53}{5}=10.6$$

Solution Steps

Subtract 2 from 4 to get 2.

$$1-\frac{2!}{5}+12-2$$

The factorial of 2 is 2.

$$1-\frac{2}{5}+12-2$$

Convert 1 to fraction \frac{5}{5}.

$$\frac{5}{5}-\frac{2}{5}+12-2$$

Since \frac{5}{5} and \frac{2}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-2}{5}+12-2$$

Subtract 2 from 5 to get 3.

$$\frac{3}{5}+12-2$$

Convert 12 to fraction \frac{60}{5}.

$$\frac{3}{5}+\frac{60}{5}-2$$

Since \frac{3}{5} and \frac{60}{5} have the same denominator, add them by adding their numerators.

$$\frac{3+60}{5}-2$$

Add 3 and 60 to get 63.

$$\frac{63}{5}-2$$

Convert 2 to fraction \frac{10}{5}.

$$\frac{63}{5}-\frac{10}{5}$$

Since \frac{63}{5} and \frac{10}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{63-10}{5}$$

Subtract 10 from 63 to get 53.

$$\frac{53}{5}$$

Factor

$$\frac{53}{5} = 10\frac{3}{5} = 10.6$$