Solve 1-(-3)^2|+sqrt{4}+sqrt[3]{-8}-(-1)^2

$$1 - ( - 3 ) ^ { 2 } | + \sqrt { 4 } + \sqrt[ 3 ] { - 8 } - ( - 1 ) ^ { 2 }$$

Evaluate

$$-8$$

Solution Steps

Calculate -3 to the power of 2 and get 9.

$$1-9|\sqrt{4}+\sqrt[3]{-8}-\left(-1\right)^{2}|$$

Calculate the square root of 4 and get 2.

$$1-9|2+\sqrt[3]{-8}-\left(-1\right)^{2}|$$

Calculate \sqrt[3]{-8} and get -2.

$$1-9|2-2-\left(-1\right)^{2}|$$

Subtract 2 from 2 to get 0.

$$1-9|0-\left(-1\right)^{2}|$$

Calculate -1 to the power of 2 and get 1.

$$1-9|0-1|$$

Subtract 1 from 0 to get -1.

$$1-9|-1|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -1 is 1.

$$1-9\times 1$$

Multiply 9 and 1 to get 9.

$$1-9$$

Subtract 9 from 1 to get -8.

$$-8$$

Factor

$$-8$$