Solve 1-(5/9+6/27+10/81)

$$1 - ( \frac { 5 } { 9 } + \frac { 6 } { 27 } + \frac { 10 } { 81 } )$$

Evaluate

$$\frac{8}{81}\approx 0.098765432$$

Solution Steps

Reduce the fraction \frac{6}{27} to lowest terms by extracting and canceling out 3.

$$1-\left(\frac{5}{9}+\frac{2}{9}+\frac{10}{81}\right)$$

Since \frac{5}{9} and \frac{2}{9} have the same denominator, add them by adding their numerators.

$$1-\left(\frac{5+2}{9}+\frac{10}{81}\right)$$

Add 5 and 2 to get 7.

$$1-\left(\frac{7}{9}+\frac{10}{81}\right)$$

Least common multiple of 9 and 81 is 81. Convert \frac{7}{9} and \frac{10}{81} to fractions with denominator 81.

$$1-\left(\frac{63}{81}+\frac{10}{81}\right)$$

Since \frac{63}{81} and \frac{10}{81} have the same denominator, add them by adding their numerators.

$$1-\frac{63+10}{81}$$

Add 63 and 10 to get 73.

$$1-\frac{73}{81}$$

Convert 1 to fraction \frac{81}{81}.

$$\frac{81}{81}-\frac{73}{81}$$

Since \frac{81}{81} and \frac{73}{81} have the same denominator, subtract them by subtracting their numerators.

$$\frac{81-73}{81}$$

Subtract 73 from 81 to get 8.

$$\frac{8}{81}$$

Factor

$$\frac{2 ^ {3}}{3 ^ {4}} = 0.09876543209876543$$