Solve 1-(4/12+3/12+2/12)=

$$1 - ( \frac { 4 } { 12 } + \frac { 3 } { 12 } + \frac { 2 } { 12 } ) =$$

Evaluate

$$\frac{1}{4}=0.25$$

Solution Steps

Since \frac{4}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$1-\left(\frac{4+3}{12}+\frac{2}{12}\right)$$

Add 4 and 3 to get 7.

$$1-\left(\frac{7}{12}+\frac{2}{12}\right)$$

Since \frac{7}{12} and \frac{2}{12} have the same denominator, add them by adding their numerators.

$$1-\frac{7+2}{12}$$

Add 7 and 2 to get 9.

$$1-\frac{9}{12}$$

Reduce the fraction \frac{9}{12} to lowest terms by extracting and canceling out 3.

$$1-\frac{3}{4}$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{4}{4}-\frac{3}{4}$$

Since \frac{4}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-3}{4}$$

Subtract 3 from 4 to get 1.

$$\frac{1}{4}$$

Factor

$$\frac{1}{2 ^ {2}} = 0.25$$