Solve 1-(2/3+1)^2-(2/7-1)^2+(5/6)^2+349/588=

$$1 - ( \frac { 2 } { 3 } + 1 ) ^ { 2 } - ( \frac { 2 } { 7 } - 1 ) ^ { 2 } + ( \frac { 5 } { 6 } ) ^ { 2 } + \frac { 349 } { 588 } =$$

Evaluate

$$-1$$

Solution Steps

Add \frac{2}{3} and 1 to get \frac{5}{3}.

$$1-\left(\frac{5}{3}\right)^{2}-\left(\frac{2}{7}-1\right)^{2}+\left(\frac{5}{6}\right)^{2}+\frac{349}{588}$$

Calculate \frac{5}{3} to the power of 2 and get \frac{25}{9}.

$$1-\frac{25}{9}-\left(\frac{2}{7}-1\right)^{2}+\left(\frac{5}{6}\right)^{2}+\frac{349}{588}$$

Subtract \frac{25}{9} from 1 to get -\frac{16}{9}.

$$-\frac{16}{9}-\left(\frac{2}{7}-1\right)^{2}+\left(\frac{5}{6}\right)^{2}+\frac{349}{588}$$

Subtract 1 from \frac{2}{7} to get -\frac{5}{7}.

$$-\frac{16}{9}-\left(-\frac{5}{7}\right)^{2}+\left(\frac{5}{6}\right)^{2}+\frac{349}{588}$$

Calculate -\frac{5}{7} to the power of 2 and get \frac{25}{49}.

$$-\frac{16}{9}-\frac{25}{49}+\left(\frac{5}{6}\right)^{2}+\frac{349}{588}$$

Subtract \frac{25}{49} from -\frac{16}{9} to get -\frac{1009}{441}.

$$-\frac{1009}{441}+\left(\frac{5}{6}\right)^{2}+\frac{349}{588}$$

Calculate \frac{5}{6} to the power of 2 and get \frac{25}{36}.

$$-\frac{1009}{441}+\frac{25}{36}+\frac{349}{588}$$

Add -\frac{1009}{441} and \frac{25}{36} to get -\frac{937}{588}.

$$-\frac{937}{588}+\frac{349}{588}$$

Add -\frac{937}{588} and \frac{349}{588} to get -1.

$$-1$$

Factor

$$-1$$