Solve 1-sqrt[3]{8}+16^frac{1{4}}-(-2)^2+27^frac{1{3}}=

$$1 - \sqrt[ 3 ] { 8 } + 16 ^ { \frac { 1 } { 4 } } - ( - 2 ) ^ { 2 } + 27 ^ { \frac { 1 } { 3 } } =$$

Evaluate

$$0$$

Solution Steps

Calculate \sqrt[3]{8} and get 2.

$$1-2+16^{\frac{1}{4}}-\left(-2\right)^{2}+27^{\frac{1}{3}}$$

Subtract 2 from 1 to get -1.

$$-1+16^{\frac{1}{4}}-\left(-2\right)^{2}+27^{\frac{1}{3}}$$

Calculate 16 to the power of \frac{1}{4} and get 2.

$$-1+2-\left(-2\right)^{2}+27^{\frac{1}{3}}$$

Add -1 and 2 to get 1.

$$1-\left(-2\right)^{2}+27^{\frac{1}{3}}$$

Calculate -2 to the power of 2 and get 4.

$$1-4+27^{\frac{1}{3}}$$

Subtract 4 from 1 to get -3.

$$-3+27^{\frac{1}{3}}$$

Calculate 27 to the power of \frac{1}{3} and get 3.

$$-3+3$$

Add -3 and 3 to get 0.

$$0$$

Factor

$$0$$